**04 a] Write a C program to compute the roots of a quadratic equation by accepting the coefficients and printing the appropriate message along with the values.**

**Answer:-**

```
#include<stdio.h>
#include<math.h>
void main()
{
float x1, x2, a, b, c, disc;
printf("Enter the coefficients a, b and c\n");
scanf("%f%f%f",&a,&b,&c);
disc=(b*b)-(4*a*c);
if(disc == 0)
{
x1= -b/(2*a);
x2= -b/(2*a);
printf("The roots are real and equal\n");
printf("1st root = %f\n",x1);
printf("2nd root = %f\n",x2);
}
else if(disc > 0)
{
x1=(-b+sqrt(disc))/(2*a);
x2=(-b-sqrt(disc))/(2*a);
printf("The roots are real and distinct\n");
printf("1st root = %f\n",x1);
printf("2nd root = %f\n",x2);
}
else
{
x1=-b/(2*a);
x2=sqrt(fabs(disc))/(2*a);
printf("The roots are imaginary\n");
printf("1st root = %f + i%f\n",x1,x2);
printf("2nd root = %f - i%f\n",x1,x2);
}
}
```

OutputEnter the coefficients a, b and c 1 2 3 The roots are imaginary 1st root = -1.000000 + i1.414214 2nd root = -1.000000 - i1.414214 Enter the coefficients a, b and c 4 4 1 The roots are real and equal 1st root = -0.500000 2nd root = -0.500000 Enter the coefficients a, b and c 3 6 2 The roots are real and distinct 1st root = -0.422650 2nd root = -1.577350