ย Ifย  ๐‘ง = ๐‘’^๐‘Ž๐‘ฅ+๐‘๐‘ฆ ๐‘“(๐‘Ž๐‘ฅ โˆ’ ๐‘๐‘ฆ),ย  show that ๐‘ (๐œ•๐‘ง/๐œ•๐‘ฅ)+ ๐‘Ž(๐œ•๐‘ง/๐œ•๐‘ฆ)= 2๐‘Ž๐‘๐‘ง

In this article, you will get the answer of ย Ifย  ๐‘ง = ๐‘’๐‘Ž๐‘ฅ+๐‘๐‘ฆ ๐‘“(๐‘Ž๐‘ฅ โˆ’ ๐‘๐‘ฆ),ย  show that ๐‘ (๐œ•๐‘ง/๐œ•๐‘ฅ)+ ๐‘Ž(๐œ•๐‘ง/๐œ•๐‘ฆ)= 2๐‘Ž๐‘๐‘ง of VTU Calculus and Differential Equation math 21MAT11 solved Modal question paper.

ย Ifย  ๐‘ง = ๐‘’๐‘Ž๐‘ฅ+๐‘๐‘ฆ ๐‘“(๐‘Ž๐‘ฅ โˆ’ ๐‘๐‘ฆ),ย  show that ๐‘ (๐œ•๐‘ง/๐œ•๐‘ฅ)+ ๐‘Ž(๐œ•๐‘ง/๐œ•๐‘ฆ)= 2๐‘Ž๐‘๐‘ง

if-๐‘ง-๐‘’๐‘Ž๐‘ฅ๐‘๐‘ฆ-๐‘“๐‘Ž๐‘ฅ-๐‘๐‘ฆ-show-that-๐‘

if-๐‘ง-๐‘’๐‘Ž๐‘ฅ๐‘๐‘ฆ-๐‘“๐‘Ž๐‘ฅ-๐‘๐‘ฆ-show-that-๐‘

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