Using method of variation of parameters, solveΒ  (𝑑2𝑦/𝑑π‘₯2) + π‘Ž2𝑦 = tanπ‘Žπ‘₯

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Using method of variation of parameters, solveΒ  (𝑑2𝑦/𝑑π‘₯2) + π‘Ž2𝑦 = tanπ‘Žπ‘₯

Answer:-

Using method of variation of parameters, solveΒ  (𝑑2𝑦/𝑑π‘₯2) + π‘Ž2𝑦 = tanπ‘Žπ‘₯

Using method of variation of parameters, solveΒ  (𝑑2𝑦/𝑑π‘₯2) + π‘Ž2𝑦 = tanπ‘Žπ‘₯

Using method of variation of parameters, solveΒ  (𝑑2𝑦/𝑑π‘₯2) + π‘Ž2𝑦 = tanπ‘Žπ‘₯

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