Solve ๐œ•^2๐‘ง/๐œ•๐‘ฅ^2=๐‘ฅ๐‘ฆ subject to the conditions ๐œ•๐‘ง/๐œ•๐‘ฅ=log(1+๐‘ฆ), when ๐‘ฅ=1 and ๐‘ง=0, when ๐‘ฅ=0.07

5.B] Solve \frac{\partial^{2} z}{\partial x^{2}} = ๐‘ฅ๐‘ฆ subject to the conditions \frac{\partial z}{\partial x} = log(1 + ๐‘ฆ), when ๐‘ฅ = 1 and ๐‘ง = 0, when ๐‘ฅ = 0.

Answer:-

Solve ๐œ•^๐‘ง/๐œ•๐‘ฅ^2=๐‘ฅ๐‘ฆ subject to the conditions ๐œ•๐‘ง/๐œ•๐‘ฅ=log(1+๐‘ฆ), when ๐‘ฅ=1 and ๐‘ง=0, when ๐‘ฅ=0.07

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