Find Using Newton’s forward interpolation

8.B] Using Newton’s forward interpolation, find \sin 48^\circ
Given:
\sin 45^\circ = 0.7071 , \sin 50^\circ = 0.7660 , \sin 55^\circ = 0.8192 , \sin 60^\circ = 0.8660

Answer:

Using Newton's forward interpolation, find <span class="wp-katex-eq" data-display="false"> \sin 48^\circ </span>
Given:
<span class="wp-katex-eq" data-display="false"> \sin 45^\circ = 0.7071 </span>, <span class="wp-katex-eq" data-display="false"> \sin 50^\circ = 0.7660 </span>, <span class="wp-katex-eq" data-display="false"> \sin 55^\circ = 0.8192 </span>, <span class="wp-katex-eq" data-display="false"> \sin 60^\circ = 0.8660 </span>

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