6.C] Find the general solution of the equation (ππ₯ β π¦)(ππ¦ + π₯) = π2π by reducing into Clairautβs form by taking the substitution π = π₯2, π = π¦2

6.C] Find the general solution of the equation (ππ₯ β π¦)(ππ¦ + π₯) = π2π by reducing into Clairautβs form by taking the substitution π = π₯2, π = π¦2