A fiber of length 1500 m has input power of 100 mW and output power of 70 mW. Find the attenuation coefficient
Formula:
The attenuation coefficient is given by:
α = -(10 / L) × log₁₀(Pout / Pin)
Given:
- L = 1500 m = 1.5 km
- Pin = 100 mW
- Pout = 70 mW
Substitution:
α = -(10 / 1.5) × log₁₀(70 / 100) = -(10 / 1.5) × log₁₀(0.7) = -(10 / 1.5) × (-0.1549) ≈ 1.03 dB/km
Final Answer:
α ≈ 1.03 dB/km