9.A] Using Runge βKutta method of order four, solve π2π¦/ππ₯2 = π¦ + π₯ ππ¦/ππ₯ for x = 0.2 , Given that , π¦(0) = 1 ,π¦β²(0) = 0
![9.A] Using Runge βKutta method of order four, solve π2π¦/ππ₯2 = π¦ + π₯ ππ¦/ππ₯ for x = 0.2 , Given that , π¦(0) = 1 ,π¦β²(0) = 0](https://i0.wp.com/vtuupdates.com/wp-content/uploads/2022/12/CamScanner-12-12-2022-19.30_watermark_page-0001.jpg?resize=1024%2C724&ssl=1)
![9.A] Using Runge βKutta method of order four, solve π2π¦/ππ₯2 = π¦ + π₯ ππ¦/ππ₯ for x = 0.2 , Given that , π¦(0) = 1 ,π¦β²(0) = 0](https://i0.wp.com/vtuupdates.com/wp-content/uploads/2022/12/CamScanner-12-12-2022-19.30_watermark_page-0002.jpg?resize=724%2C1024&ssl=1)
![9.A] Using Runge βKutta method of order four, solve π2π¦/ππ₯2 = π¦ + π₯ ππ¦/ππ₯ for x = 0.2 , Given that , π¦(0) = 1 ,π¦β²(0) = 0](https://i0.wp.com/vtuupdates.com/wp-content/uploads/2022/12/CamScanner-12-12-2022-19.30_watermark_page-0003.jpg?resize=724%2C1024&ssl=1)
9.A] Using Runge βKutta method of order four, solve π2π¦/ππ₯2 = π¦ + π₯ ππ¦/ππ₯ for x = 0.2 , Given that , π¦(0) = 1 ,π¦β²(0) = 0