Ifย  ๐‘ข = ๐‘“(2๐‘ฅ โˆ’ 3๐‘ฆ,3๐‘ฆ โˆ’ 4๐‘ง,4๐‘ง โˆ’ 2๐‘ฅ), show that 6๐‘ขx + 4๐‘ข๐‘ฆ + 3uz = 0

In this article, you will get the answer of Ifย  ๐‘ข = ๐‘“(2๐‘ฅ โˆ’ 3๐‘ฆ,3๐‘ฆ โˆ’ 4๐‘ง,4๐‘ง โˆ’ 2๐‘ฅ), show that 6๐‘ขx + 4๐‘ข๐‘ฆ + 3uz = 0ย ย of VTU Calculus and Differential Equation math 21MAT11 solved Modal question paper.

Ifย  ๐‘ข = ๐‘“(2๐‘ฅ โˆ’ 3๐‘ฆ,3๐‘ฆ โˆ’ 4๐‘ง,4๐‘ง โˆ’ 2๐‘ฅ), show that 6๐‘ขx + 4๐‘ข๐‘ฆ + 3uz = 0

Answer:-

if-๐‘ข-๐‘“2๐‘ฅโˆ’3๐‘ฆ3๐‘ฆโˆ’4๐‘ง4๐‘งโˆ’2๐‘ฅ-show-that-6๐‘ขx-4๐‘ข

if-๐‘ข-๐‘“2๐‘ฅโˆ’3๐‘ฆ3๐‘ฆโˆ’4๐‘ง4๐‘งโˆ’2๐‘ฅ-show-that-6๐‘ขx-4๐‘ข

if-๐‘ข-๐‘“2๐‘ฅโˆ’3๐‘ฆ3๐‘ฆโˆ’4๐‘ง4๐‘งโˆ’2๐‘ฅ-show-that-6๐‘ขx-4๐‘ข

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