Evaluate the pivotal values of the equation π’π‘π‘ = 16π’π₯π₯ , taking h = 1 up to t = 1.25. The boundary condition are π’(0,π‘) = π’(5,π‘) = 0,π’π‘(π₯,0) = 0 and π’(π₯,0) = π₯2(5 β π₯)
In this article, you will get the answer ofΒ Evaluate the pivotal values of the equation π’π‘π‘ = 16π’π₯π₯ , taking h = 1 up to t = 1.25. The boundaryβ¦