Find the general solution of the equation
6.C] Find the general solution of the equation (ππ₯ β π¦)(ππ¦ + π₯) = π2π by reducing into Clairautβs form by taking the substitution π = π₯2, π = π¦2
6.C] Find the general solution of the equation (ππ₯ β π¦)(ππ¦ + π₯) = π2π by reducing into Clairautβs form by taking the substitution π = π₯2, π = π¦2
6.B] When a switch is closed in a circuit containing a battery E, a resistance R and an inductance L, the current i build up at a rate given by L di dt Ri = E. Find i as aβ¦
6.A] Solve (π₯2 + π¦2 + π₯)ππ₯ + π₯π¦ππ¦ = 0
5.C] Solve π₯π¦π2β(π₯2 + π¦2)π+π₯π¦ = 0
5.B] Find the orthogonal trajectories of π₯2 /π2 +π¦2/π2+π= 1, where Ξ» is a parameter.
5.A] Solve ππ¦/ππ₯ + π¦/π₯= π₯2π¦6
4.C] If π₯ + π¦ + π§ = π’, π¦ + π§ = π£ πππ π§ = π’π£π€, find the values of π(π₯,π¦,π§)/π(π’,π£,π€).
4.B] If π’ = π(π₯ β π¦, π¦ β π§, π§ β π₯) show that ππ’/ππ₯ + ππ’/ππ¦ +ππ’/ππ§ = 0
4.A] Evaluate i) . ii)
3.C] Find the extreme values of the function π(π₯, π¦) = π₯ 3 + 3π₯π¦ 2 β 3π¦ 2 β 3π₯ 2 + 4