10.A] Apply Milneβs method to solve π2π¦/ππ₯2 = 1 +ππ¦ ππ₯ at x = 0.4. given that
π¦(0) = 1 , π¦(0.1) = 1.1103, π¦(0.2) = 1.2427 , π¦(0.3) = 1.399
π¦β²(0) = 1 ,π¦β²(0.1) = 1.2103,π¦β²(0.2) = 1.4427,π¦β²(0.3) = 1.699
![10.A] Apply Milneβs method to solve π2π¦/ππ₯2 = 1 +ππ¦ ππ₯ at x = 0.4. given that
π¦(0) = 1 , π¦(0.1) = 1.1103, π¦(0.2) = 1.2427 , π¦(0.3) = 1.399
π¦β²(0) = 1 ,π¦β²(0.1) = 1.2103,π¦β²(0.2) = 1.4427,π¦β²(0.3) = 1.699](https://i0.wp.com/vtuupdates.com/wp-content/uploads/2022/12/CamScanner-12-12-2022-19.38_watermark_page-0001.jpg?resize=724%2C1024&ssl=1)
![10.A] Apply Milneβs method to solve π2π¦/ππ₯2 = 1 +ππ¦ ππ₯ at x = 0.4. given that
π¦(0) = 1 , π¦(0.1) = 1.1103, π¦(0.2) = 1.2427 , π¦(0.3) = 1.399
π¦β²(0) = 1 ,π¦β²(0.1) = 1.2103,π¦β²(0.2) = 1.4427,π¦β²(0.3) = 1.699](https://i0.wp.com/vtuupdates.com/wp-content/uploads/2022/12/CamScanner-12-12-2022-19.38_watermark_page-0002.jpg?resize=724%2C1024&ssl=1)